When the same amount of zinc is treated separately with excess of sulphuric acid and excess of sodium hydroxide, the ratio of volumes of hydrogen evolved is

Question

When the same amount of zinc is treated separately with excess of sulphuric acid and excess of sodium hydroxide, the ratio of volumes of hydrogen evolved is (A) 1: 1 (B) 1: 2 (C) 2: 1 (D) 9: 4

Tardigrade Admin · Accepted Answer

Zn + H 2 SO 4 arrow ZnSO 4+ H 2 Zn +2 NaOH arrow Na 2 ZnO 2+ H 2

Q. When the same amount of zinc is treated separately with excess of sulphuric acid and excess of sodium hydroxide, the ratio of volumes of hydrogen evolved is

$1 : 1$

$1 : 2$

$2 : 1$

$9 : 4$

$Z n + H_{2} S O_{4} \to Z n S O_{4} + H_{2}$
$Z n + 2 N a O H \to N a_{2} Z n O_{2} + H_{2}$