Initially, the current will pass through the
capacitor (and not through the resistance which is
parallel to capacitor). So effective resistance in the
circuit is RAB. Therefore the current in the resistor
is 2 mA. After some time, the capacitor will become
fully charged and will be in its steady state. Now
no current will pass through the capacitor and the
effective resistance of the circuit will be (1000 +
1000) = 2000 Ω. Therefore current in the resistor =RV=20002=1×10−3A=1mA.