When the gap is closed without placing any object in the screw gauge whose least count is 0.005 mm, the 5th division on its circular scale coincides with the reference line on main scale, and when a small sphere is placed, the reading on main scale advances by 4 divisions, whereas circular scale reading advances by five times to the corresponding reading when no object was placed. There are 200 divisions on the circular scale. The radius of the sphere is

Question

When the gap is closed without placing any object in the screw gauge whose least count is 0.005 mm, the 5th division on its circular scale coincides with the reference line on main scale, and when a small sphere is placed, the reading on main scale advances by 4 divisions, whereas circular scale reading advances by five times to the corresponding reading when no object was placed. There are 200 divisions on the circular scale. The radius of the sphere is (A) 4.10 mm (B) 4.05 mm (C) 2.10 mm (D) 2.05 mm

Tardigrade Admin · Accepted Answer

MSD = 200 × 0.005 = 1 mm 2r = 4 × 1 + 25 × 0.005 - 5 × 0.005 = 4.1 r = 2.05 mm

$4.10 mm$

$4.05 mm$

$2.10 mm$

$2.05 mm$

$MS D = 200 \times 0.005 = 1 mm$
$2 r = 4 \times 1 + 25 \times 0.005 - 5 \times 0.005$
$= 4.1$
$r = 2.05 mm$

4.10mm

4.05mm

2.10mm

2.05mm

MSD=200×0.005=1mm 2r=4×1+25×0.005−5×0.005 =4.1 r=2.05mm

$4.10 mm$

$4.05 mm$

$2.10 mm$

$2.05 mm$

$MS D = 200 \times 0.005 = 1 mm$
$2 r = 4 \times 1 + 25 \times 0.005 - 5 \times 0.005$
$= 4.1$
$r = 2.05 mm$