When the current in a coil changes from 8 A to 2 A in 3 × 10-2 s, the e.m.f. induced in the coil is 2 volt. The self-inductance of the coil (in millihenry) is

Question

When the current in a coil changes from 8 A to 2 A in 3 × 10-2 s, the e.m.f. induced in the coil is 2 volt. The self-inductance of the coil (in millihenry) is (A) 1 (B) 5 (C) 20 (D) 10

Tardigrade Admin · Accepted Answer

e=-L (d i/d t) ⇒ 2=-L((2-8/3 × 10-2)) ⇒ L=0.01 H =10 mH

Q. When the current in a coil changes from $8 A$ to $2 A$ in $3 \times 1 0^{- 2} s$ , the e.m.f. induced in the coil is $2$ volt. The self-inductance of the coil (in millihenry) is

1

5

20

10

$e = - L \frac{d i}{d t} \Rightarrow 2 = - L (\frac{2 - 8}{3 \times 1 0 ^{- 2}})$
$\Rightarrow L = 0.01 H = 10 m H$

Q. When the current in a coil changes from 8A to 2A in 3×10−2s, the e.m.f. induced in the coil is 2 volt. The self-inductance of the coil (in millihenry) is

1

5

20

10

e=−Ldtdi​⇒2=−L(3×10−22−8​) ⇒L=0.01H=10mH

Q. When the current in a coil changes from $8 A$ to $2 A$ in $3 \times 1 0^{- 2} s$ , the e.m.f. induced in the coil is $2$ volt. The self-inductance of the coil (in millihenry) is

$e = - L \frac{d i}{d t} \Rightarrow 2 = - L (\frac{2 - 8}{3 \times 1 0 ^{- 2}})$
$\Rightarrow L = 0.01 H = 10 m H$