When same amount of zinc is treated separately with excess of sulphuric acid and excess of sodium hydroxide solution, the ratio of volumes of hydrogen evolved is:

Question

When same amount of zinc is treated separately with excess of sulphuric acid and excess of sodium hydroxide solution, the ratio of volumes of hydrogen evolved is: (A) 1: 1 (B) 1: 2 (C) 2: 1 (D) 9: 4

Tardigrade Admin · Accepted Answer

The reactions of zinc with sulphuric acid and excess of sodium hydroxide separately are given below:

Z n + 2 N a O H \to N a_{2} Z n O_{2} + H_{2}

Z n + H_{2} S O_{4} \to Z n S O_{4} + H_{2}

In both the reactions,

1

mole of

H_{2}

is evolved.
Hence, the ratio of volumes of hydrogen evolved is

1 : 1

.

Q. When same amount of zinc is treated separately with excess of sulphuric acid and excess of sodium hydroxide solution, the ratio of volumes of hydrogen evolved is:

1 : 1

1 : 2

2 : 1

9 : 4

Q. When same amount of zinc is treated separately with excess of sulphuric acid and excess of sodium hydroxide solution, the ratio of volumes of hydrogen evolved is:

1 : 1

1 : 2

2 : 1

9 : 4

The reactions of zinc with sulphuric acid and excess of sodium hydroxide separately are given below: Zn+2NaOH→Na2​ZnO2​+H2​ Zn+H2​SO4​→ZnSO4​+H2​ In both the reactions, 1 mole of H2​ is evolved. Hence, the ratio of volumes of hydrogen evolved is 1:1.