Question

When copper reacts with hot and conc. $H_{2}S{O}_4$ it gives

• A. $H_2$
• B. $N_2$
• C. $O_2$
• D. $S{O}_2$

Answer 1

Answer: (D)

$\underset{\text{(hot, conc.)}}{Cu+2H_{2}S{O}_4}\to CuS{O}_4+S{O}_2+2H_{2}O$