When Cl2 gas reacts with hot and concentrated sodium hydroxide solution, the oxidation number of chlorine changes from:

Question

When Cl2 gas reacts with hot and concentrated sodium hydroxide solution, the oxidation number of chlorine changes from: (A) zero to +1 and zero to -5 (B) zero to -1 and zero to +5 (C) zero to -1 and zero to +3 (D) zero to +1 and zero to -3

Tardigrade Admin · Accepted Answer

Q. When $C l_{2}$ gas reacts with hot and concentrated sodium hydroxide solution, the oxidation number of chlorine changes from:

zero to $+ 1$ and zero to $- 5$

zero to $- 1$ and zero to $+ 5$

zero to $- 1$ and zero to $+ 3$

zero to $+ 1$ and zero to $- 3$

Q. When Cl2​ gas reacts with hot and concentrated sodium hydroxide solution, the oxidation number of chlorine changes from:

zero to +1 and zero to −5

zero to −1 and zero to +5

zero to −1 and zero to +3

zero to +1 and zero to −3

Q. When $C l_{2}$ gas reacts with hot and concentrated sodium hydroxide solution, the oxidation number of chlorine changes from:

zero to $+ 1$ and zero to $- 5$

zero to $- 1$ and zero to $+ 5$

zero to $- 1$ and zero to $+ 3$

zero to $+ 1$ and zero to $- 3$