When CH 2= CH - COOH is reduced with LiAlH4, the compound obtained will be:

Question

When CH 2= CH - COOH is reduced with LiAlH4, the compound obtained will be: (A) CH 3- CH 2- COOH (B) CH 2= CH - CH 2 OH (C) CH 3- CH 2- CH 2 OH (D) CH 3- CH 2- CHO

Tardigrade Admin · Accepted Answer

LiAlH4 reduces - COOH to - CH 2 OH without affective C = C bond

Q. When $C H_{2} = C H - COO H$ is reduced with $L i A l H_{4}$ , the compound obtained will be:

$C H_{3} - C H_{2} - COO H$

$C H_{2} = C H - C H_{2} O H$

$C H_{3} - C H_{2} - C H_{2} O H$

$C H_{3} - C H_{2} - C H O$

$L i A l H_{4}$ reduces $- COO H$ to $- C H_{2} O H$ without affective $C = C$ bond

Q. When CH2​=CH−COOH is reduced with LiAlH4​, the compound obtained will be:

CH3​−CH2​−COOH

CH2​=CH−CH2​OH

CH3​−CH2​−CH2​OH

CH3​−CH2​−CHO