When C 2 H 2, CH 4 and C 2 H 4 pass through a test tube which has ammonical Cu 2 Cl 2, find out which gas comes out unaffected from test tube?

Question

When C 2 H 2, CH 4 and C 2 H 4 pass through a test tube which has ammonical Cu 2 Cl 2, find out which gas comes out unaffected from test tube? (A) C 2 H 2 and CH 4 (B) C 2 H 2 and C 2 H 4 (C) C 2 H 4 and CH 4 (D) C 2 H 2

Tardigrade Admin · Accepted Answer

C 2 H 2 forms copper acetylide with ammonical Cu 2 Cl 2 Cu 2 Cl 2+2 NH 4 OH arrow Cu 2 O + H 2 O +2 NH 4 Cl Cu 2 O + C 2 H 2 arrow underset text(copper acetylide)Cu 2 C 2+ H 2 O

Q. When $C_{2} H_{2}, C H_{4}$ and $C_{2} H_{4}$ pass through a test tube which has ammonical $C u_{2} C l_{2}$ , find out which gas comes out unaffected from test tube?

$C_{2} H_{2}$ and $C H_{4}$

$C_{2} H_{2}$ and $C_{2} H_{4}$

$C_{2} H_{4}$ and $C H_{4}$

$C_{2} H_{2}$

$C_{2} H_{2}$ forms copper acetylide with ammonical $C u_{2} C l_{2}$ $C u_{2} C l_{2} + 2 N H_{4} O H \to C u_{2} O + H_{2} O + 2 N H_{4} Cl$ $C u_{2} O + C_{2} H_{2} \to (copper acetylide) C u_{2} C_{2} + H_{2} O$

Q. When C2​H2​,CH4​ and C2​H4​ pass through a test tube which has ammonical Cu2​Cl2​, find out which gas comes out unaffected from test tube?

C2​H2​ and CH4​

C2​H2​ and C2​H4​

C2​H4​ and CH4​

C2​H2​