When an aqueous solution of copper (II) sulphate is saturated with ammonia, the blue compound crystallises on evaporation. The formula of this blue compound is:

Question

When an aqueous solution of copper (II) sulphate is saturated with ammonia, the blue compound crystallises on evaporation. The formula of this blue compound is: (A) [Cu(NH3)4]SO4. H2O (square planar) (B) [Cu(NH3)4]SO4 (Tetrahedral) (C) [Cu(NH3)6]SO4 (Octahedral) (D) [Cu(SO4) (NH3)5] (Octahedral)

Tardigrade Admin · Accepted Answer

The aqueous solution of copper(II) sulphate reacts with ammonia to form blue colored crystalline complex

[C u (N H_{3})_{4}] S O_{4} \cdot H_{2} O

C u S O_{4} + 4 N H_{3} + H_{2} O \to [C u (N H_{3})_{4}] S O_{4} \cdot H_{2} O

The

C u^{2 +}

ion undergoes dsp

^{2}

hybridization which results in square planar geometry.

Q. When an aqueous solution of copper (II) sulphate is saturated with ammonia, the blue compound crystallises on evaporation. The formula of this blue compound is:

$[C u (N H_{3})_{4}] S O_{4} . H_{2} O$ (square planar)

$[C u (N H_{3})_{4}] S O_{4}$ (Tetrahedral)

$[C u (N H_{3})_{6}] S O_{4}$ (Octahedral)

$[C u (S O_{4}) (N H_{3})_{5}]$ (Octahedral)

Q. When an aqueous solution of copper (II) sulphate is saturated with ammonia, the blue compound crystallises on evaporation. The formula of this blue compound is:

[Cu(NH3​)4​]SO4​.H2​O (square planar)

[Cu(NH3​)4​]SO4​ (Tetrahedral)

[Cu(NH3​)6​]SO4​ (Octahedral)

[Cu(SO4​)(NH3​)5​] (Octahedral)

The aqueous solution of copper(II) sulphate reacts with ammonia to form blue colored crystalline complex [Cu(NH3​)4​]SO4​⋅H2​O CuSO4​+4NH3​+H2​O→[Cu(NH3​)4​]SO4​⋅H2​O The Cu2+ ion undergoes dsp 2 hybridization which results in square planar geometry.

$[C u (N H_{3})_{4}] S O_{4} . H_{2} O$ (square planar)

$[C u (N H_{3})_{4}] S O_{4}$ (Tetrahedral)

$[C u (N H_{3})_{6}] S O_{4}$ (Octahedral)

$[C u (S O_{4}) (N H_{3})_{5}]$ (Octahedral)