When acrobat bends his body (assume no external torque)

Question

When acrobat bends his body (assume no external torque) (A) I text acrobat decreases (B) I text acrobat increases (C) ω text acrobat increases (D) Both (a) and (c)

Tardigrade Admin · Accepted Answer

By the conservation of angular momentum, we know that

I ω =

constant.
As the acrobat bends his body, then moment of inertia

I

will decrease and hence

ω

of acrobat will increase as no external torque is acting on the acrobat.

Q. When acrobat bends his body (assume no external torque)

$I_{acrobat}$ decreases

$I_{acrobat}$ increases

$ω_{acrobat}$ increases

Both (a) and (c)

By the conservation of angular momentum, we know that $I ω =$ constant.
As the acrobat bends his body, then moment of inertia $I$ will decrease and hence $ω$ of acrobat will increase as no external torque is acting on the acrobat.

Q. When acrobat bends his body (assume no external torque)

Iacrobat ​ decreases

Iacrobat ​ increases

ωacrobat ​ increases

Both (a) and (c)

By the conservation of angular momentum, we know that Iω= constant. As the acrobat bends his body, then moment of inertia I will decrease and hence ω of acrobat will increase as no external torque is acting on the acrobat.

$I_{acrobat}$ decreases

$I_{acrobat}$ increases

$ω_{acrobat}$ increases

By the conservation of angular momentum, we know that $I ω =$ constant.
As the acrobat bends his body, then moment of inertia $I$ will decrease and hence $ω$ of acrobat will increase as no external torque is acting on the acrobat.