Q. When a proton is accelerated through $1 V$ , then its kinetic energy will be

4237 230 AIPMTAIPMT 1999Dual Nature of Radiation and Matter Report Error

A

1 eV

57%

B

13.6 eV

19%

C

1840eV

10%

D

0.54eV

14%

Solution:

$K . E . = 1.6 \times 1 0^{- 19} \times 1 = 1 e V .$