When a polyatomic gas undergoes an adiabatic process, its temperature and volume are related by the equation TVγ-1= constant, the value of n will be

Question

When a polyatomic gas undergoes an adiabatic process, its temperature and volume are related by the equation TV&gamma;-1= constant, the value of n will be (A) 1.33 (B) 0.33 (C) 2.33 (D) 1

Tardigrade Admin · Accepted Answer

For adiabatic process TV&gamma;-1= constant For polyatomic gas &gamma;=(4/3)=1.33 n=1.33-1=0.33

Q. When a polyatomic gas undergoes an adiabatic process, its temperature and volume are related by the equation $T V^{γ - 1} =$ constant, the value of $n$ will be

$1.33$

$0.33$

$2.33$

$1$

For adiabatic process
$T V^{γ - 1} =$ constant
For polyatomic gas
$γ = \frac{4}{3} = 1.33 n = 1.33 - 1 = 0.33$

Q. When a polyatomic gas undergoes an adiabatic process, its temperature and volume are related by the equation TVγ−1= constant, the value of n will be

1.33

0.33

2.33

1

For adiabatic process TVγ−1= constant For polyatomic gas γ=34​=1.33n=1.33−1=0.33

Q. When a polyatomic gas undergoes an adiabatic process, its temperature and volume are related by the equation $T V^{γ - 1} =$ constant, the value of $n$ will be

$1.33$

$0.33$

$2.33$

$1$

For adiabatic process
$T V^{γ - 1} =$ constant
For polyatomic gas
$γ = \frac{4}{3} = 1.33 n = 1.33 - 1 = 0.33$