Q.
When a force F1 is applied on a metallic wire, the length of the wire is L1. If a force F2 is applied on the same wire, the length of the wire is L2. The original length of the wire L is
Change in length of wire of length L is directly proportional to the external force applied F1∝(L1−L) ⇒F1=K(L1−L).......(i)
Similarly, F2=K(L2−L)......(ii)
Dividing Eq. (i) by Eq. (ii), we get F2F1=L2−LL1−L ⇒F1L2−F1L=F2L1−F2L ⇒L=F1−F2F1L2−F2L1