Q. When a $_{4} B e^{9}$ is bombarded with $α$ - particle, one of the products of nuclear transmutations is $_{6} C^{12}$ . If other is

1893 215 Atoms Report Error

A

$_{- 1} e^{0}$

8%

B

$_{1} H^{1}$

24%

C

$_{1} H^{2}$

28%

D

$_{0} n^{1}$

40%

Solution:

$_{4} B e^{9} +_{2} H e^{4} \to_{6} C^{12} +_{0} n^{1}$