When 90 Th 228 transforms to 83 Bi 212, then the number to the emitted α and β-particles are, respectively

Question

When 90 Th 228 transforms to 83 Bi 212, then the number to the emitted α and β-particles are, respectively (A) 8 α, 7 β (B) 4 α, 7 β (C) 4 α, 4 β (D) 4 α, 1 β

Tardigrade Admin · Accepted Answer

Z=90 T hA=228 arrow=83 B iA prime=212 Number of α-particles emitted nα=(A-A prime/4)=(228-212/4)=4 Number of β-particles emitted nβ=2 nα-Z+Z prime=2 × 4-90+83=1 text .

Q. When $_{90} T h^{228}$ transforms to $_{83} B i^{212}$ , then the number to the emitted $α$ and $β$ -particles are, respectively

$8 α, 7 β$

$4 α, 7 β$

$4 α, 4 β$

$4 α, 1 β$

$Z =_{90} T h^{A = 228} \to=_{83} B i^{A^{'} = 212}$
Number of $α$ -particles emitted
$n_{α} = \frac{A - A ^{'}}{4} = \frac{228 - 212}{4} = 4$
Number of $β$ -particles emitted
$n_{β} = 2 n_{α} - Z + Z^{'} = 2 \times 4 - 90 + 83 = 1 .$

Q. When 90​Th228 transforms to 83​Bi212, then the number to the emitted α and β-particles are, respectively

8α,7β

4α,7β

4α,4β

4α,1β