Q. What will be the pH of $1 \times 1 0^{- 4} M H_{2} S O_{4}$ solution?

3209 243 Equilibrium Report Error

A

$10.4$

6%

B

$3.70$

87%

C

$3$

5%

D

$13$

2%

Solution:

$H_{2} S O_{4} ⇌ 2 H + + S O^{2 -} 4$
$[H^{+}] = 2 \times 1 \times 1 0^{- 4} M$
$p H = - l o g (2 \times 1 0^{- 4})$
$= 3.70$