Lower resistance on extreme left and upper resistance on extreme right are ineffective.
The resistance R2 and R3 are in series combination.
Therefore their equivalent resistance, R′=R2+R3=10+10=20Ω.
Similarly, the resistance R5 and R6 are in series combination.
Therefore their equivalent resistance, R′′=R5+R6=10+10=20Ω.
Now the equivalent resistances R′ and R′′ are in parallel combination.
Therefore their equivalent resistance. R′′′=R′+R′′R′R′′=20+2020×20=40400=10Ω.
Thus equivalent resistance between A and D,R=R1+R′′′+R4=10+10+10=30Ω(∵
series combination)