Question

What will be the end product $(B)$ in the following sequence of reactions?

• A. 1, 2 -dibromobenzene
• B. 1, 2 -dibromobenzaldehyde
• C. 1, 3 -dibromobenzene
• D. 1, 4 -dibromobenzene

Answer 1

Answer: (C)

$KMn{O}_4$ (alkaline) converts the alkyl chain attached directly to benzene nucleus into $—COOK$ group. Hydrolysis converts $—COOK$ into $—COOH$ group i.e., we get a carboxylic acid
The carboxylic acid group when fused with hot sodalime $(NaOH+CaO)$, it gets converted into $—H$ with the removal of $C{O}_2$ gas, (decarboxylation step).