What will be the emf for the given cell? Pt |H2(g, P1) | H+(aq) || H2(g, P2) | Pt

Question

What will be the emf for the given cell? Pt |H2(g, P1) | H+(aq) || H2(g, P2) | Pt (A) (RT/F) In (P1/P2) (B) (RT/2F) In (P1/P2) (C) (RT/F) In (P2/P1) (D) (RT/2F) In (P2/P1)

Tardigrade Admin · Accepted Answer

H 2( P 1)+2 H +(1 M ) arrow 2 H +(1 M )+ H 2( P 2) E text cell = E text cell 0-( RT /2 F ) In =0-( RT /2 F ) In ( P 1/ P 2)[. for concentration cell, .E text cell °=0] =( RT /2 F ) In ( P 1/ P 2)

Q. What will be the emf for the given cell?
$Pt ∣ H_{2} (g, P_{1}) ∣ H_{(a q)}^{+} ∣∣ H_{2} (g, P_{2}) ∣ Pt$

$\frac{RT}{F}$ In $\frac{P _{1}}{P _{2}}$

$\frac{RT}{2 F}$ In $\frac{P _{1}}{P _{2}}$

$\frac{RT}{F}$ In $\frac{P _{2}}{P _{1}}$

$\frac{RT}{2 F}$ In $\frac{P _{2}}{P _{1}}$

$H_{2} (P_{1}) + 2 H^{+} (1 M) \to 2 H^{+} (1 M) + H_{2} (P_{2})$
$E_{cell} = E_{cell}^{0} - \frac{RT}{2 F} I n$
$= 0 - \frac{RT}{2 F} I n \frac{P 1}{P 2} [$ for concentration cell, $E_{cell}^{\circ} = 0]$
$= \frac{RT}{2 F} I n \frac{P 1}{P 2}$

Q. What will be the emf for the given cell? Pt∣H2​(g,P1​)∣H(aq)+​∣∣H2​(g,P2​)∣Pt

FRT​ In P2​P1​​

2FRT​ In P2​P1​​

FRT​ In P1​P2​​

2FRT​ In P1​P2​​