What will be the acceleration of an object due to gravity if it is placed at a distance of (R/2) from the centre of earth. Knowing mass is distributed uniformly, (.g= acceleration due to gravity on the surface of earth and R is the radius of earth). Assume mass of earth is distributed uniformly.

Question

What will be the acceleration of an object due to gravity if it is placed at a distance of (R/2) from the centre of earth. Knowing mass is distributed uniformly, (.g= acceleration due to gravity on the surface of earth and R is the radius of earth). Assume mass of earth is distributed uniformly. (A) g (B) 2g (C) (g/2) (D) None of these.

Tardigrade Admin · Accepted Answer

The acceleration due to gravity at a distance x(.x < R.) from centre of earth (of radius R ) is g(.x.)=g(x/R)∴ g((R/2))=(g/2)

$g$

$2 g$

$\frac{g}{2}$

None of these.

The acceleration due to gravity at a distance $x (x < R)$ from centre of earth (of radius $R$ ) is
$g (x) = g \frac{x}{R} ∴ g (\frac{R}{2}) = \frac{g}{2}$

Q. What will be the acceleration of an object due to gravity if it is placed at a distance of 2R​ from the centre of earth. Knowing mass is distributed uniformly, (g= acceleration due to gravity on the surface of earth and R is the radius of earth). Assume mass of earth is distributed uniformly.

g

2g

2g​

None of these.

The acceleration due to gravity at a distance x(x<R) from centre of earth (of radius R ) is g(x)=gRx​∴g(2R​)=2g​

$g$

$2 g$

$\frac{g}{2}$

The acceleration due to gravity at a distance $x (x < R)$ from centre of earth (of radius $R$ ) is
$g (x) = g \frac{x}{R} ∴ g (\frac{R}{2}) = \frac{g}{2}$