Question

What percent of length of a wire will increase by applying a stress of 1 kg. $wt/m{m}^2$ on it $(Y=1\times 10^{11}N{m}^{-2}$ and 1 kg wt = 9.8N]

• A. 0.0078%
• B. 0.0088%
• C. 0.0098%
• D. 0.0067%

Answer 1

Answer: (C)

$\frac{e}{l}\times 100=\frac{F}{AY}\times 100$