What mass of calcium chloride in grams would be enough to produce 14.35 g of AgCl ? (Atomic mass Ca=40, Ag =108)

Question

What mass of calcium chloride in grams would be enough to produce 14.35 g of AgCl ? (Atomic mass Ca=40, Ag =108) (A) 5.55 g (B) 8.295 g (C) 11.19 g (D) 16.59 g

Tardigrade Admin · Accepted Answer

CaCl 2+2 AgNO 3 arrow Ca ( NO 3)2+2 AgCl 1.1 g CaCl 2 required to produce 2 × 143.5 g of AgCl =111 g CaCl 2 required to produce 14.35 g of AgCl =(111 × 14.35/2 × 143.5) =5.55 g

Q. What mass of calcium chloride in grams would be enough to produce $14.35 g$ of $A g Cl$ ? (Atomic mass $C a = 40, A g = 108$ )

$5.55 g$

$8.295 g$

$11.19 g$

$16.59 g$

$C a C l_{2} + 2 A g N O_{3} \to C a (N O_{3})_{2} + 2 A g Cl$
$1.1 g C a C l_{2}$ required to produce
$2 \times 143.5 g$ of $A g Cl = 111 g$
$C a C l_{2}$ required to produce $14.35 g$ of
$A g Cl = \frac{111 \times 14.35}{2 \times 143.5}$
$= 5.55 g$

Q. What mass of calcium chloride in grams would be enough to produce 14.35g of AgCl ? (Atomic mass Ca=40,Ag=108)

5.55g

8.295g

11.19g

16.59g