Tardigrade
Tardigrade - CET NEET JEE Exam App
Exams
Login
Signup
Tardigrade
Question
Chemistry
What is the standard reduction potential (E°) for Fe3+ → Fe ? Given that: Fe2+ + 2e- arrow Fe ; E°Fe2+ / Fe = - 0.47 V Fe3+ + e- arrow Fe2+ ; E°Fe3+ / Fe2+ = + 0.77 V
Q. What is the standard reduction potential
(
E
∘
)
for
Fe
X
3
+
→
Fe
?
Given that :
F
e
2
+
+
2
e
−
→
F
e
;
E
F
e
2
+
/
F
e
∘
=
−
0.47
V
F
e
3
+
+
e
−
→
F
e
2
+
;
E
F
e
3
+
/
F
e
2
+
∘
=
+
0.77
V
5558
208
JEE Main
JEE Main 2017
Electrochemistry
Report Error
A
−
0.057
V
38%
B
+
0.057
V
30%
C
+
0.30
V
26%
D
−
0.30
V
6%
Solution:
Correct answer is (a)
−
0.057
V