What is the shortest distance of the point (1, 2, 3) from x- axis ?

Question

What is the shortest distance of the point (1, 2, 3) from x- axis ? (A) 1 (B) √6 (C) √13 (D) √14

Tardigrade Admin · Accepted Answer

Any point on x-axis has y = z = 0 Distance of the point (1, 2, 3) from x-axis is the distance between point (1, 2, 3) and point (1, 0, 0) =√(1-1)2 + (2-0)2 +(3-0)2 = √22 + 32 = √4+9 = √13

Q. What is the shortest distance of the point (1, 2, 3) from x- axis ?

1

$6$

$13$

$14$

Any point on x-axis has y = z = 0
Distance of the point (1, 2, 3) from x-axis is the distance between point (1, 2, 3) and point (1, 0, 0)
$= (1 - 1)^{2} + (2 - 0)^{2} + (3 - 0)^{2} = 2^{2} + 3^{2}$
$= 4 + 9 = 13$

Q. What is the shortest distance of the point (1, 2, 3) from x- axis ?

1

6​

13​

14​

Any point on x-axis has y = z = 0 Distance of the point (1, 2, 3) from x-axis is the distance between point (1, 2, 3) and point (1, 0, 0) =(1−1)2+(2−0)2+(3−0)2​=22+32​ =4+9​=13​

$6$

$13$

$14$

Any point on x-axis has y = z = 0
Distance of the point (1, 2, 3) from x-axis is the distance between point (1, 2, 3) and point (1, 0, 0)
$= (1 - 1)^{2} + (2 - 0)^{2} + (3 - 0)^{2} = 2^{2} + 3^{2}$
$= 4 + 9 = 13$