Question

What is the oxidation state of $P$ in $Ba(H_{2}P{O}_2{)}_2$ ?

• A. +1
• B. +2
• C. +3
• D. -1

Answer 1

Answer: (A)

Let the oxidation state of $P$ is $x$, then
$2(+1)+2[2(+1)+x+2(-2)]=0$
$2+2(2+x-4)=02+4+2x-8$
$=02+2x-4=0$
$2x=2x=+1$