What is the equivalent weight of P in the following reaction? P4+ NaOH → NaH2 PO2 +PH3

Question

What is the equivalent weight of P in the following reaction? P4+ NaOH → NaH2 PO2 +PH3 (A) (31/4) (B) (31/3) (C) (31/2) (D) 31 × 4/3

Tardigrade Admin · Accepted Answer

P4 → NaH2 PO2 (P4)o → 4P+ +4e- ∴ Eq. wt. (Reductant) =(P4/4) (P4)o+12e →4p3- ∴ Eq. wt. (Oxidant)=(P4/12) ∴ Eq. wt. (P4)=(P4/12)+(P4/12) =P4×(16/48)=(4×31/3)=31×(4/3)

Q. What is the equivalent weight of P in the following reaction?
$P_{4} + N a O H \to N a H_{2} P O_{2} + P H_{3}$

$\frac{31}{4}$

$\frac{31}{3}$

$\frac{31}{2}$

$31 \times 4/3$

Q. What is the equivalent weight of P in the following reaction? P4​+NaOH→NaH2​PO2​+PH3​

431​

331​

231​

31×4/3

P4​→NaH2​PO2​ (P4​)o→4P++4e− ∴Eq.wt.(Reductant)=4P4​​ (P4​)o+12e→4p3− ∴Eq.wt.(Oxidant)=12P4​​ ∴Eq.wt.(P4​)=12P4​​+12P4​​ =P4​×4816​=34×31​=31×34​

Q. What is the equivalent weight of P in the following reaction?
$P_{4} + N a O H \to N a H_{2} P O_{2} + P H_{3}$

$\frac{31}{4}$

$\frac{31}{3}$

$\frac{31}{2}$

$31 \times 4/3$