What is the entropy change in 2 mol N2, when its temperature is taken from 400 K to 800 K, at constant pressure?

Question

What is the entropy change in 2 mol N2, when its temperature is taken from 400 K to 800 K, at constant pressure? (A) 30 J/K (B) 60 J/K (C) 40 J/K (D) 20 J/K

Tardigrade Admin · Accepted Answer

Δ S=nCp in (T2/T1)=2×(7/2)R× in (800/400)=40 J/K

Q. What is the entropy change in 2 mol N₂, when its temperature is taken from 400 K to 800 K, at constant pressure?

30 J/K

60 J/K

40 J/K

20 J/K

$Δ S = n C_{p} in \frac{T _{2}}{T _{1}} = 2 \times \frac{7}{2} R \times in \frac{800}{400} = 40$ J/K

Q. What is the entropy change in 2 mol N2, when its temperature is taken from 400 K to 800 K, at constant pressure?