What is the energy of activation of a reaction if its rate doubles when the temperature is raised from 290 K to 300 K ?

Question

What is the energy of activation of a reaction if its rate doubles when the temperature is raised from 290 K to 300 K ? (A)  12 kcal  (B) 41 kcal (C) 13.8 kcal (D) 52 kcal

Tardigrade Admin · Accepted Answer

log (k2/k1) =(Ea/2.303R) ([T2 - T-1/[T1T2) log2 =(Ea/2,303× 2) ([300-290]/[290 × 300]) (k2 =2K2 ,R=2 cal/ K mol) Ea=12062 calories ≈ 12 kcal

Q. What is the energy of activation of a reaction if its rate doubles when the temperature is raised from $290 K$ to $300 K$ ?

$12 k c a l$

$41 k c a l$

$13.8 k c a l$

$52 k c a l$

$l o g \frac{k _{2}}{k _{1}} = \frac{E _{a}}{2.303 R} \frac{[ T _{2} - T - 1}{[ T _{1} T _{2}}$
$l o g 2 = \frac{E a}{2 , 303 \times 2} \frac{[ 300 - 290 ]}{[ 290 \times 300 ]}$
$(k_{2} = 2 K_{2}, R = 2 c a l / K m o l)$
$E a = 12062 c a l or i es \approx 12 k c a l$

Q. What is the energy of activation of a reaction if its rate doubles when the temperature is raised from 290K to 300K ?

12kcal

41kcal

13.8kcal

52kcal