Question

What is the empirical formula of a compound composed of $O$ & $Mn$ in equal weight ratio? (At. wt of $Mn=55$ )

• A. $MnO$
• B. $Mn{O}_2$
• C. $M{n}_2{O}_3$
• D. $M{n}_2{O}_7$

Answer 1

Answer: (D)

$Mn=xgm=\frac{x}{55}=0.018x$

$O=xgm=\frac{x}{16}=0.0625x$

$\frac{0.018x}{0.018x}=1$

$\Rightarrow \frac{0.0625x}{0.018x}\approx 3.5$

$M{n}_1{O}_{3.5}\Rightarrow M{n}_2{O}_7$