What is the electrode potential (in volt) of the following electrode at 25°C ? Ni2+ (0.1 M) | Ni(g) standard reduction potential of Ni2+ / Ni is - 0.25 V, ((2.303RT/F) =0.06)

Question

What is the electrode potential (in volt) of the following electrode at 25°C ? Ni2+ (0.1 M) | Ni(g) standard reduction potential of Ni2+ / Ni is - 0.25 V, ((2.303RT/F) =0.06) (A) -0.82 V (B) -0.22 V (C) -0.28 V (D) -0.34 V

Tardigrade Admin · Accepted Answer

By Nernst equation E=E°-(RT/nF) ln [(Ni(s)/Ni2+)]=-0.25-(0.06/2)log[(1/0.1)] =-0.25-0.03 =-0.28 V

Q. What is the electrode potential (in volt) of the following electrode at $2 5^{\circ} C$ ?
$N i^{2 +} (0.1 M) ∣ N i_{(g)}$
standard reduction potential of $N i^{2 +} / N i$ is $- 0.25 V$ , $(\frac{2.303 RT}{F} = 0.06)$

$- 0.82 V$

$- 0.22 V$

$- 0.28 V$

$- 0.34 V$

By Nernst equation
$E = E^{\circ} - \frac{RT}{n F}$
ln $[\frac{N i _{(s)}}{N i ^{2 +}}] = - 0.25 - \frac{0.06}{2} l o g [\frac{1}{0.1}]$
$= - 0.25 - 0.03$
$= - 0.28 V$

Q. What is the electrode potential (in volt) of the following electrode at 25∘C ? Ni2+(0.1M)∣Ni(g)​ standard reduction potential of Ni2+/Ni is −0.25V, (F2.303RT​=0.06)

−0.82V

−0.22V

−0.28V

−0.34V