What is the dimensional formula for magnetic flux?

Question

What is the dimensional formula for magnetic flux? (A) [M L2 T- 2 A- 1] (B) [M L3 T- 2 A- 2] (C) [M0 L- 2 T- 2 A- 2] (D) [M L2 T- 1 A2]

Tardigrade Admin · Accepted Answer

Magnetic flux is given as φ=B S cos θ ...(i) Here is B magnetic field and S is area. Magnetic force F on a charge q moving with velocity v is given as F=q v B sin β So, B=(F/q v sin β) .............(ii) By equations (i) and (ii) φ=(F/q v sin β) × S cos θ Trigonometric functions are dimensionless so φ=(F S/q v)=(M L T-2 × L2/A T × L T-1)=M L2 T-2 A-1

Q. What is the dimensional formula for magnetic flux?

$[M L^{2} T^{- 2} A^{- 1}]$

$[M L^{3} T^{- 2} A^{- 2}]$

$[M^{0} L^{- 2} T^{- 2} A^{- 2}]$

$[M L^{2} T^{- 1} A^{2}]$

Q. What is the dimensional formula for magnetic flux?

[ML2T−2A−1]

[ML3T−2A−2]

[M0L−2T−2A−2]

[ML2T−1A2]

$[M L^{2} T^{- 2} A^{- 1}]$

$[M L^{3} T^{- 2} A^{- 2}]$

$[M^{0} L^{- 2} T^{- 2} A^{- 2}]$

$[M L^{2} T^{- 1} A^{2}]$