What is the co-ordination number of sodium in Na2O ?

Question

What is the co-ordination number of sodium in Na2O ? (A) 6 (B) 4 (C) 8 (D) 2

Tardigrade Admin · Accepted Answer

Na 2 O has antifluorite structure. O 2- ions constitute a ccp lattice and Na + ions occupy the tetrahedral voids, each O 2- ion is in contact with 8 Na + ions and each Na + ion is in contact with 4 O 2- ions. Thus C. N. of sodium in Na 2 O =4.

Q. What is the co-ordination number of sodium in $N a_{2} O$ ?

6

4

8

2

$N a_{2} O$ has antifluorite structure. $O^{2 -}$ ions constitute a ccp lattice and $N a^{+}$ ions occupy the tetrahedral voids, each $O^{2 -}$ ion is in contact with $8 N a^{+}$ ions and each $N a^{+}$ ion is in contact with $4 O^{2 -}$ ions. Thus $C$ . $N$ . of sodium in $N a_{2} O = 4$ .

Q. What is the co-ordination number of sodium in Na2​O ?

6

4

8

2

Na2​O has antifluorite structure. O2− ions constitute a ccp lattice and Na+ ions occupy the tetrahedral voids, each O2− ion is in contact with 8Na+ ions and each Na+ ion is in contact with 4O2− ions. Thus C. N. of sodium in Na2​O=4.

Q. What is the co-ordination number of sodium in $N a_{2} O$ ?

$N a_{2} O$ has antifluorite structure. $O^{2 -}$ ions constitute a ccp lattice and $N a^{+}$ ions occupy the tetrahedral voids, each $O^{2 -}$ ion is in contact with $8 N a^{+}$ ions and each $N a^{+}$ ion is in contact with $4 O^{2 -}$ ions. Thus $C$ . $N$ . of sodium in $N a_{2} O = 4$ .