Tardigrade
Tardigrade - CET NEET JEE Exam App
Exams
Login
Signup
Tardigrade
Question
Physics
What is 273.00 K on the celsius scale of temperature?
Q. What is 273.00 K on the celsius scale of temperature?
1935
218
Thermal Properties of Matter
Report Error
A
−
0.1
5
∘
C
42%
B
0.0
0
∘
C
47%
C
0.1
5
∘
C
9%
D
273.1
5
∘
C
2%
Solution:
273.15
K
=
0
∘
C
Celsius scale = Kelvin scale
−
273.15