Question

What hybrid orbitals will form the following compound $H_{3}C—CH=CH—C{H}_2—C{H}_3$

• A. $sp$ and $s{p}^3$
• B. $s{p}^2$ and $s{p}^3$
• C. $sp$ and $s{p}^2$
• D. Only $s{p}^3$

Answer 1

Answer: (B)

$s{p}^2$ and $s{p}^3$
$\underset{s{p}^3}{C{H}_3}-\underset{s{p}^2}{\mathrm{CH}}=\underset{s{p}^2}{\mathrm{CH}}-\underset{s{p}^3}{C{H}_2}-\underset{s{p}^3}{C{H}_3}$