Water falls from a height 500 m . The rise in temperature of water at bottom if whole of the energy remains in water, will be: (specific heat of water is c=4.2 kJ / kg )

Question

Water falls from a height 500 m . The rise in temperature of water at bottom if whole of the energy remains in water, will be: (specific heat of water is c=4.2 kJ / kg ) (A) 0.23° C (B) 1.16° C (C) 0.96° C (D) 1.02° C

Tardigrade Admin · Accepted Answer

Potential energy = increase in heat of water. From law of conservation of energy, we know that energy can neither be created nor destroyed, it remains conserved. When water falls from a height, it has potential energy (m g h), this is used in heating up the water (m c Δ θ). Hence, we have m g h=m c Δ θ ⇒ Δ θ=(g h/c) =(9.8 × 500/4.2 × 103)=1.16° C

Q. Water falls from a height $500 m .$ The rise in temperature of water at bottom if whole of the energy remains in water, will be : (specific heat of water is $c = 4.2 k J / k g$ )

$0.2 3^{\circ} C$

$1.1 6^{\circ} C$

$0.9 6^{\circ} C$

$1.0 2^{\circ} C$

Q. Water falls from a height 500m. The rise in temperature of water at bottom if whole of the energy remains in water, will be : (specific heat of water is c=4.2kJ/kg )

0.23∘C

1.16∘C

0.96∘C

1.02∘C

Q. Water falls from a height $500 m .$ The rise in temperature of water at bottom if whole of the energy remains in water, will be : (specific heat of water is $c = 4.2 k J / k g$ )

$0.2 3^{\circ} C$

$1.1 6^{\circ} C$

$0.9 6^{\circ} C$

$1.0 2^{\circ} C$