Θf(x)=x3+3(a−7)x2+3(a2−9)x−1 ⇒f′(x)=3x2+6(a−7)x+3(a2−9)
For f(x) to have a positive point of maximum, both roots of f′(x) should be distinct and greater than 0 ∴ Both roots of x2+2(a−7)x+(a2−9)=0 are greater than zero
(i)D>0⇒4(a−7)2−4(a2−9)>0 ⇒−14a+58>0⇒a<729
(ii) a2−9>0⇒a<−3 or a>3
(iii) 2⋅1−2(a−7)>0⇒a<7 ∴a∈(−∞,−3)∪(3,429)