Using Young's double slit experiment, a monochromatic light of wavelength 5000 mathringA produces fringes of fringe width 0.5 mm. If another monochromatic light of wavelength 6000 mathringA is used and the separation between the slits is doubled, then the new fringe width will be :

Question

Using Young's double slit experiment, a monochromatic light of wavelength 5000 mathringA produces fringes of fringe width 0.5 mm. If another monochromatic light of wavelength 6000 mathringA is used and the separation between the slits is doubled, then the new fringe width will be : (A) 0.5 mm (B) 1.0 mm (C) 0.6 mm (D) 0.3 mm

Tardigrade Admin · Accepted Answer

Fringe width β=( D λ/ d ) λ1=5000 mathringA β1=( D / d )(5000 × 10-10)=5 × 10-4 m ldots (I) β2=( D /(2 d ))(6000 × 10-10)= x (let) ...(II) Divide (II) (I) (β2/β1)=(3000 × 10-10/5000 × 10-10)=( x /5 × 10-4) x =3 × 10-4 m or 0.3 mm

Q. Using Young's double slit experiment, a monochromatic light of wavelength 5000A˚ produces fringes of fringe width 0.5mm. If another monochromatic light of wavelength 6000A˚ is used and the separation between the slits is doubled, then the new fringe width will be :

0.5 mm

1.0 mm

0.6 mm

0.3 mm

Fringe width β=dDλ​ λ1​=5000A˚ β1​=dD​(5000×10−10)=5×10−4m… (I) β2​=(2d)D​(6000×10−10)=x (let) ...(II) Divide (II) & (I) β1​β2​​=5000×10−103000×10−10​=5×10−4x​ x=3×10−4m or 0.3mm