Using the provided information in the following paper chromatogram: the calculate R f value of A × 10-1

Question

Using the provided information in the following paper chromatogram: <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/mathematics/4f20b544c633706a9be412e0e5c915f6-.png" /> the calculate R f value of A × 10-1 (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

R f =( text Distance travelled by compound / text Distance travelled by solvent ) on chromatogram distance travelled by cmopound is arrow 2 cm Distance travelled by solvent =5 cm So R f =(2/5)=4 × 10-1=0.4

Q. Using the provided information in the following paper chromatogram :

the calculate $R_{f}$ value of $A$ ____ $\times 1 0^{- 1}$

$R_{f} = \frac{Distance travelled by compound}{Distance travelled by solvent}$

on chromatogram distance travelled by cmopound is $\to 2 c m$

Distance travelled by solvent $= 5 c m$

So $R_{f} = \frac{2}{5} = 4 \times 1 0^{- 1} = 0.4$

Q. Using the provided information in the following paper chromatogram : the calculate Rf​ value of A ____ ×10−1

Rf​= Distance travelled by solvent Distance travelled by compound ​ on chromatogram distance travelled by cmopound is →2cm Distance travelled by solvent =5cm So Rf​=52​=4×10−1=0.4

Q. Using the provided information in the following paper chromatogram :

the calculate $R_{f}$ value of $A$ ____ $\times 1 0^{- 1}$

$R_{f} = \frac{Distance travelled by compound}{Distance travelled by solvent}$

on chromatogram distance travelled by cmopound is $\to 2 c m$

Distance travelled by solvent $= 5 c m$

So $R_{f} = \frac{2}{5} = 4 \times 1 0^{- 1} = 0.4$