Use the data of below and find out the most stable oxidised species. E°Cr2O2-7/Cr3+=1.33 V ; E°Cl2/Cl-=1.36 V E°MnO-4/Mn2+=1.51 V ; E°Cr3+/Cr=-0.74 V

Question

Use the data of below and find out the most stable oxidised species. E°Cr2O2-7/Cr3+=1.33 V ; E°Cl2/Cl-=1.36 V E°MnO-4/Mn2+=1.51 V ; E°Cr3+/Cr=-0.74 V (A) Cr3+ (B) MnO-4 (C) Cr2O2-7 (D) Mn2+

Tardigrade Admin · Accepted Answer

E°Cr3+/Cr has lowest reduction potential hence, Cr3+ is the most stable oxidised species.

Q. Use the data of below and find out the most stable oxidised species.
$E_{C r_{2} O_{7}^{2 -} / C r^{3 +}}^{\circ} = 1.33 V$ ; $E_{C l_{2} / C l^{-}}^{\circ} = 1.36 V$
$E_{M n O_{4}^{-} / M n^{2 +}}^{\circ} = 1.51 V$ ; $E_{C r^{3 +} / C r}^{\circ} = - 0.74 V$

$C r^{3 +}$

$M n O_{4}^{-}$

$C r_{2} O_{7}^{2 -}$

$M n^{2 +}$

$E_{C r^{3 +} / C r}^{\circ}$ has lowest reduction potential hence, $C r^{3 +}$ is the most stable oxidised species.

Q. Use the data of below and find out the most stable oxidised species. ECr2​O72−​/Cr3+∘​=1.33V ; ECl2​/Cl−∘​=1.36V EMnO4−​/Mn2+∘​=1.51V ; ECr3+/Cr∘​=−0.74V

Cr3+

MnO4−​

Cr2​O72−​

Mn2+