Ultraviolet radiation of 6.2 eV falls on an aluminium surface (work function 4.2 eV). The kinetic energy of the faster electron emitted is approximately

Question

Ultraviolet radiation of 6.2 eV falls on an aluminium surface (work function 4.2 eV). The kinetic energy of the faster electron emitted is approximately (A) 3.2× 10- 15 J (B) 3.2× 10- 17 J (C) 3.2× 10- 19 J (D) 3.2× 10- 21 J

Tardigrade Admin · Accepted Answer

KE of emitted electron is EK=hν -W = 6.2 texte textV - 4.2 texte textV = 2.0 texte textV = 2× 1.6× 10- 19 textJ = 3.2× 10- 19 textJ

Q. Ultraviolet radiation of 6.2 eV falls on an aluminium surface (work function 4.2 eV). The kinetic energy of the faster electron emitted is approximately

$3.2 \times 1 0^{- 15}$ J

$3.2 \times 1 0^{- 17}$ J

$3.2 \times 1 0^{- 19}$ J

$3.2 \times 1 0^{- 21}$ J

KE of emitted electron is
$E_{K} = h ν$ -W
$= 6.2 e V - 4.2 e V = 2.0 e V$
$= 2 \times 1.6 \times 1 0^{- 19} J$
$= 3.2 \times 1 0^{- 19} J$

Q. Ultraviolet radiation of 6.2 eV falls on an aluminium surface (work function 4.2 eV). The kinetic energy of the faster electron emitted is approximately

3.2×10−15 J

3.2×10−17 J

3.2×10−19 J

3.2×10−21 J

KE of emitted electron is EK​=hν -W =6.2eV−4.2eV=2.0eV =2×1.6×10−19J =3.2×10−19J

$3.2 \times 1 0^{- 15}$ J

$3.2 \times 1 0^{- 17}$ J

$3.2 \times 1 0^{- 19}$ J

$3.2 \times 1 0^{- 21}$ J

KE of emitted electron is
$E_{K} = h ν$ -W
$= 6.2 e V - 4.2 e V = 2.0 e V$
$= 2 \times 1.6 \times 1 0^{- 19} J$
$= 3.2 \times 1 0^{- 19} J$