Two Zener diodes (A and B) having breakdown voltages of 6 V and 4 V respectively, are connected as shown in athe circuit below. The output voltage V 0 variation with input voltage linearly increasing with time, is given by: ( V text input =0 V . at t =0 ) (figures are qualitative)

Question

Two Zener diodes (A and B) having breakdown voltages of 6 V and 4 V respectively, are connected as shown in athe circuit below. The output voltage V 0 variation with input voltage linearly increasing with time, is given by: ( V text input =0 V . at t =0 ) (figures are qualitative) (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

Till input voltage Reaches 4 V No zener is in Breakdown Region So V 0= V i Then Now when V i changes between 4 V to 6 V One Zener with 4 V will Breakdown are P.D. across This Zener will become constant and Remaining Potential will drop. aero Resistance in series with 4 V Zener. Now current in circuit increases Abruptly and source must have an internal resistance due to which. Some potential will get drop across the source also so correct graph between V 0 and t. will be <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/2a0ceb18d845dcfbd4f9a3a264424a37-.png" /> We have to Assume some resistance in series with source.

Q. Two Zener diodes (A and B) having breakdown voltages of 6V and 4V respectively, are connected as shown in athe circuit below. The output voltage V0​ variation with input voltage linearly increasing with time, is given by : (Vinput ​=0V at t=0 ) (figures are qualitative)

Q. Two Zener diodes (A and B) having breakdown voltages of $6 V$ and $4 V$ respectively, are connected as shown in athe circuit below. The output voltage $V_{0}$ variation with input voltage linearly increasing with time, is given by : $(V_{input} = 0 V$ at $t = 0$ ) (figures are qualitative)