Q.
Two wires have resistances R and 2R . When both are joining in series and in parallel, then ratio of heats generated in these situations on applying the same voltage, is:
In series combination, the net resistance Rs=R+2R=3R
Heat produced in Rs, Hs=RsV2=3RV2...(i)
In parallel combination, the net resistance Rp=R+2RR×2R=3R2R2=32R
Heat produced in Rp Hp=RpV2=2R/3VR=2R3V2...(ii)
Dividing Eq. (i) by Eq. (ii), we obtain HpHs=3V2/2RV2/3R=92