Two sources of light emit X-rays of wavelength 1 nm and visible light of wavelength 500 nm respectively. Both the sources emit light of the same power 200 W. The ratio of the number density of photons of X-rays to the number densitty of photons of the visible light of the given wavelengths is:

Question

Two sources of light emit X-rays of wavelength 1 nm and visible light of wavelength 500 nm respectively. Both the sources emit light of the same power 200 W. The ratio of the number density of photons of X-rays to the number densitty of photons of the visible light of the given wavelengths is: (A) (1/500) (B) 500 (C) 250 (D) (1/250)

Tardigrade Admin · Accepted Answer

P =( nhc /λ t ) ∴ ( n 1/ n 2)=(λ1/λ2)=(1/500)

$\frac{1}{500}$

$500$

$250$

$\frac{1}{250}$

$P = \frac{nh c}{λ t}$
$∴ \frac{n _{1}}{n _{2}} = \frac{λ _{1}}{λ _{2}} = \frac{1}{500}$

Q. Two sources of light emit X-rays of wavelength 1nm and visible light of wavelength 500nm respectively. Both the sources emit light of the same power 200W. The ratio of the number density of photons of X-rays to the number densitty of photons of the visible light of the given wavelengths is:

5001​

500

250

2501​

P=λtnhc​ ∴n2​n1​​=λ2​λ1​​=5001​

$\frac{1}{500}$

$500$

$250$

$\frac{1}{250}$

$P = \frac{nh c}{λ t}$
$∴ \frac{n _{1}}{n _{2}} = \frac{λ _{1}}{λ _{2}} = \frac{1}{500}$