Two solutions of a substance (non electrolyte) arc mixed in the following manner. 480 mL of 1.5 M first solution +520 mL of 1.2 M second solution. What is the molarity of the final mixture ?

Question

Two solutions of a substance (non electrolyte) arc mixed in the following manner. 480 mL of 1.5 M first solution +520 mL of 1.2 M second solution. What is the molarity of the final mixture ? (A) 2.70 M (B) 1.344 M (C) 1.50 M (D) 1.20 M

Tardigrade Admin · Accepted Answer

Total molarity = (M1V1+M2V2/V1+V2) = (1.5×480+ 1.2× 520/480+ 520) = 1.344 M

Q. Two solutions of a substance (non electrolyte) arc mixed in the following manner. 480 mL of 1.5 M first solution +520 mL of 1.2 M second solution. What is the molarity of the final mixture ?

2.70 M

1.344 M

1.50 M

1.20 M

Total molarity $= \frac{M _{1} V _{1} + M _{2} V _{2}}{V _{1} + V _{2}}$
$= \frac{1.5 \times 480 + 1.2 \times 520}{480 + 520}$
$= 1.344 M$

Q. Two solutions of a substance (non electrolyte) arc mixed in the following manner. 480 mL of 1.5 M first solution +520 mL of 1.2 M second solution. What is the molarity of the final mixture ?

2.70 M

1.344 M

1.50 M

1.20 M

Total molarity =V1​+V2​M1​V1​+M2​V2​​ =480+5201.5×480+1.2×520​ =1.344M

Total molarity $= \frac{M _{1} V _{1} + M _{2} V _{2}}{V _{1} + V _{2}}$
$= \frac{1.5 \times 480 + 1.2 \times 520}{480 + 520}$
$= 1.344 M$