Q.
Two solids dissociate as follows A(s)⇌B(g)+C(g);Kp1=xatm2 D(s)⇌C(g)+E(g);KP2=yatm2
The total pressure when both the solids dissociate simultaneously is :
A(s)⇌P1B(g)+P1C(g)x=P1(P1+P2)KP1=x=PB.PC ....(1) D(s)⇌P2C(g)+P2E(g)y=(P1+P2)(P2)KP2=y=PC.PE ...(2)
Adding (1) and (2) x+y=(P1+P2)2
Now total pressure PT=PC+PB+PE =(P1+P2)+P1+P2=2(P1+P2) PT=2(x+y)