Two solid conductors are made up of same material, have same length and same resistance. One of them has a circular cross section of area A1 and the other one has a square cross section of area A2. The ratio A1/A2 is

Question

Two solid conductors are made up of same material, have same length and same resistance. One of them has a circular cross section of area A1 and the other one has a square cross section of area A2. The ratio A1/A2 is (A) 1.5 (B) 1 (C) 0.8 (D) 2

Tardigrade Admin · Accepted Answer

R=ρ (ℓ/A) R1=R2 (1/A1)=(1/A2) (A1/A2)=1

Q. Two solid conductors are made up of same material, have same length and same resistance. One of them has a circular cross section of area $A_{1}$ and the other one has a square cross section of area $A_{2}$ . The ratio $A_{1} / A_{2}$ is

$1.5$

$1$

$0.8$

$2$

$R = ρ \frac{ℓ}{A}$
$R_{1} = R_{2} < b r > \frac{1}{A _{1}} = \frac{1}{A _{2}}$
$\frac{A _{1}}{A _{2}} = 1$

Q. Two solid conductors are made up of same material, have same length and same resistance. One of them has a circular cross section of area A1​ and the other one has a square cross section of area A2​. The ratio A1​/A2​ is

1.5

1

0.8

2

R=ρAℓ​ R1​=R2​<br>A1​1​=A2​1​ A2​A1​​=1

Q. Two solid conductors are made up of same material, have same length and same resistance. One of them has a circular cross section of area $A_{1}$ and the other one has a square cross section of area $A_{2}$ . The ratio $A_{1} / A_{2}$ is

$1.5$

$1$

$0.8$

$2$

$R = ρ \frac{ℓ}{A}$
$R_{1} = R_{2} < b r > \frac{1}{A _{1}} = \frac{1}{A _{2}}$
$\frac{A _{1}}{A _{2}} = 1$