Two resistors are joined in parallel whose resultant is (6/5) Ω. One of the resistance wire is broken and the effective resistance becomes 2 ohms. Then the resistance (in ohm) of the wire that got broken is

Question

Two resistors are joined in parallel whose resultant is (6/5) Ω. One of the resistance wire is broken and the effective resistance becomes 2 ohms. Then the resistance (in ohm) of the wire that got broken is (A) (6/5) (B) 2 (C) (3/5) (D) 3

Tardigrade Admin · Accepted Answer

(R1 R2/R1+R2)=(6/5) R1=2 (2 R2/2+R2)=(6/5) 5 R2=6+3 R2 2 R2=6 R2=3 Ω

Q. Two resistors are joined in parallel whose resultant is $\frac{6}{5} Ω$ . One of the resistance wire is broken and the effective resistance becomes $2$ ohms. Then the resistance (in ohm) of the wire that got broken is

$\frac{6}{5}$

$2$

$\frac{3}{5}$

$3$

$\frac{R _{1} R _{2}}{R _{1} + R _{2}} = \frac{6}{5}$
$R_{1} = 2$
$\frac{2 R _{2}}{2 + R _{2}} = \frac{6}{5}$
$5 R_{2} = 6 + 3 R_{2}$
$2 R_{2} = 6$
$R_{2} = 3 Ω$

Q. Two resistors are joined in parallel whose resultant is 56​Ω. One of the resistance wire is broken and the effective resistance becomes 2 ohms. Then the resistance (in ohm) of the wire that got broken is

56​

2

53​

3

R1​+R2​R1​R2​​=56​ R1​=2 2+R2​2R2​​=56​ 5R2​=6+3R2​ 2R2​=6 R2​=3Ω

Q. Two resistors are joined in parallel whose resultant is $\frac{6}{5} Ω$ . One of the resistance wire is broken and the effective resistance becomes $2$ ohms. Then the resistance (in ohm) of the wire that got broken is

$\frac{6}{5}$

$2$

$\frac{3}{5}$

$3$

$\frac{R _{1} R _{2}}{R _{1} + R _{2}} = \frac{6}{5}$
$R_{1} = 2$
$\frac{2 R _{2}}{2 + R _{2}} = \frac{6}{5}$
$5 R_{2} = 6 + 3 R_{2}$
$2 R_{2} = 6$
$R_{2} = 3 Ω$