Two points separated by 0.05 mm can just be inspected in a microscope when light of wavelength 6000 mathringA is used. If light of wavelength 3000 mathringA is used then the limit of resolution becomes

Question

Two points separated by 0.05 mm can just be inspected in a microscope when light of wavelength 6000 mathringA is used. If light of wavelength 3000 mathringA is used then the limit of resolution becomes (A) 0.05 mm (B) 0.025 mm (C) 0.1 mm (D) 0.15 mm

Tardigrade Admin · Accepted Answer

Resolving power of a microscope is the shorter distance between two seperate point in a microscope's field of view that can be seen directly.
Resolving power

\propto \frac{λ}{2 a}

(

a =

aperture)

\frac{d _{1}}{d _{2}} = \frac{λ _{1}}{λ _{2}}

\Rightarrow \frac{0.05}{d _{2}} = \frac{6000}{3000}

\Rightarrow 0.025 mm

Q. Two points separated by 0.05mm can just be inspected in a microscope when light of wavelength 6000A˚ is used. If light of wavelength 3000A˚ is used then the limit of resolution becomes

0.05 mm

0.025 mm

0.1 mm

0.15 mm

Resolving power of a microscope is the shorter distance between two seperate point in a microscope's field of view that can be seen directly. Resolving power ∝2aλ​ (a= aperture) d2​d1​​=λ2​λ1​​ ⇒d2​0.05​=30006000​ ⇒0.025mm

Q. Two points separated by $0.05 mm$ can just be inspected in a microscope when light of wavelength $6000 \overset{˚}{A}$ is used. If light of wavelength $3000 \overset{˚}{A}$ is used then the limit of resolution becomes