Two particles execute SHM of same amplitude and frequency along the same straight line. They pass one another when going in opposite directions, each time their displacement is half of their amplitude. The phase difference between them is

Question

Two particles execute SHM of same amplitude and frequency along the same straight line. They pass one another when going in opposite directions, each time their displacement is half of their amplitude. The phase difference between them is (A) 90° (B) 30° (C) 120° (D) 60°

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/49b6677810df5c9af17bc605d93b5ac5-.png" /> Δ φ=φ2-φ1=(5 π/6)-(π/6)=(4 π/6)=(2 π/3) =120°

Q. Two particles execute SHM of same amplitude and frequency along the same straight line. They pass one another when going in opposite directions, each time their displacement is half of their amplitude. The phase difference between them is

$9 0^{\circ}$

$3 0^{\circ}$

$12 0^{\circ}$

$6 0^{\circ}$

$Δ ϕ = ϕ_{2} - ϕ_{1} = \frac{5 π}{6} - \frac{π}{6} = \frac{4 π}{6} = \frac{2 π}{3}$
$= 12 0^{\circ}$